8c^2-2c+1=4c

Solution for 8c^2-2c+1=4c equation:

Simplifying
8c2 + -2c + 1 = 4c

Reorder the terms:
1 + -2c + 8c2 = 4c

Solving
1 + -2c + 8c2 = 4c

Solving for variable 'c'.

Reorder the terms:
1 + -2c + -4c + 8c2 = 4c + -4c

Combine like terms: -2c + -4c = -6c
1 + -6c + 8c2 = 4c + -4c

Combine like terms: 4c + -4c = 0
1 + -6c + 8c2 = 0

Factor a trinomial.
(1 + -4c)(1 + -2c) = 0

Subproblem 1
Set the factor '(1 + -4c)' equal to zero and attempt to solve:

Simplifying
1 + -4c = 0

Solving
1 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -4c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4c = 0 + -1
-4c = 0 + -1

Combine like terms: 0 + -1 = -1
-4c = -1

Divide each side by '-4'.
c = 0.25

Simplifying
c = 0.25
Subproblem 2
Set the factor '(1 + -2c)' equal to zero and attempt to solve:

Simplifying
1 + -2c = 0

Solving
1 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2c = 0 + -1
-2c = 0 + -1

Combine like terms: 0 + -1 = -1
-2c = -1

Divide each side by '-2'.
c = 0.5

Simplifying
c = 0.5
Solution
c = {0.25, 0.5}